The voltage and current across a resistor are in phase, so the graphs are the same shape. The equations should be:
a) I(t)=I₀cos(ωt) and V(t)=V₀cos(ωt) OR
b) I(t)=I₀cos(ωt+φ) and V(t)=V₀cos(ωt+φ)
not a mixture.
If φ=0, then equations a) and b) are the same of course.
So just draw the current graph the same shape as your voltage graph. Draw one graph underneath the other, to help make it clear that they follow the same pattern.
Remember to label the amplitudes I₀ and V₀ on the graphs; and label the period (e.g. peak to peak) as T = 2π/ω.
If φ =0, the shape is a shown in the link. Use the right hand part (positive x). Use V and t, I and t, as axes instead of y and x.
If φ is not zero, then don't start the curve at the maximum.
The values π, 2π, 3π, 4π, in the link should be changed to π/ω, 2π/ω, 3π/ω, 4π/ω.
Answers & Comments
Verified answer
The voltage and current across a resistor are in phase, so the graphs are the same shape. The equations should be:
a) I(t)=I₀cos(ωt) and V(t)=V₀cos(ωt) OR
b) I(t)=I₀cos(ωt+φ) and V(t)=V₀cos(ωt+φ)
not a mixture.
If φ=0, then equations a) and b) are the same of course.
So just draw the current graph the same shape as your voltage graph. Draw one graph underneath the other, to help make it clear that they follow the same pattern.
Remember to label the amplitudes I₀ and V₀ on the graphs; and label the period (e.g. peak to peak) as T = 2π/ω.
If φ =0, the shape is a shown in the link. Use the right hand part (positive x). Use V and t, I and t, as axes instead of y and x.
If φ is not zero, then don't start the curve at the maximum.
The values π, 2π, 3π, 4π, in the link should be changed to π/ω, 2π/ω, 3π/ω, 4π/ω.