4a^2 * 3b^3/(2b) =

(4/2)a^2 * 3b^(3 - 1) =

2a^2 * 3b^2 =

6a^2 b^2

4a^2 * 3b^3 / 2b

= 6a^2 b^2

I'm guessing you mean 4a²·3b³/(2b). The parentheses matter.

4a²·3b³/(2b) = 2a²·3b² = 6a²b²

(4a^2 * 3b^3)/2b = 2a^2 * 3b^2

= 6a^2b^2

assuming this is

4a²•3b³/2b

or is it

4a²•3b3³/2b

or is it

4a²•(3b)³/2b

I'll do the first

4a²•3b³/2b

2a²•3b²

6a²b²

you will get much better answers if you use proper terminology. that is use of parans, and ^ for exponentiation.

4a²•3b³/2b =

4a²•3b³

--------- =

....2b

// Note that 2b in the denominator is the same as 2b¹.

// The b³ in the numerator can cancel with the b¹ in

// the denominator leaving b³/b=b² in the numerator

// and b/b=1 in the denominator

4a²•3b²

--------- =

....2(1)

// The 4 in the numerator can also cancel with the

// 2 in the denominator leaving 4/2 = 2 in the numerator

// and 2/2=1 in the denominator

2a²•3b²

--------- =

....1

2a²•3b²..............ANS