Seja n = 8^2 log2 15 - log2 45. Então o valor de 'n' é:?
a) 5²
b) 8³
c) 2^5
d) 5³
ps: com os cálculos
ps2: n = 8 elevado a 2 log de 15 na base 2 menos log de 45 na base 2
More Questions From This User See All
a) 5²
b) 8³
c) 2^5
d) 5³
ps: com os cálculos
ps2: n = 8 elevado a 2 log de 15 na base 2 menos log de 45 na base 2
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
n = 8^(2*log[2](15) - log[2](45))
n = 8^log[2](15²/45)
n = 8^log[2](225/45)
n = 8^log[2](5)
n = 2^(3log[2](5)
n = 2^(log[2](5³)
n = 5³
.