He applies a force of 85.0 N along the shaft of a 2.27 kg push broom so that it makes an angle between the handle and the ground of 44.0°.
If the broom is pushed at constant velocity, what is the coefficient of friction between the broom and the floor?
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He applies a force of F = 85.0 N along the shaft of a m = 2.27 kg push broom so that it makes an angle between the handle and the ground of theta = 44.0°.
So the normal N = F sin(theta) + mg, the horizontal force Fx = F cos(theta), and the net force in the XX direction f = kN - Fx = 0.
So we have k = Fx/N = F cos(theta)/(F sin(theta) + mg) = 85*cos(radians(44))/(85*sin(radians(44)) + 2.27* 9.81) = 0.751941678 ANS.