well, hello from France !
"and it goes like this..."
f(x) = (1-x)(tan(πx/2))
we will use the result :
lim (a ----> 0) tan(a)/a = 1
so
let be : e = 1 - x, we then have :
(1-x)(tan(πx/2)) = e tan( (π/2)(1 - e) )
= e tan( π/2 - πe/2)
= e / tan(πe/2)
= (2/π) (πe/2) / tan(πe/2) ------> 2 / π
so for a = πe/2 ----> 0 when e -----> 0 (when x > 1)
lim ( x -----> 1 of ) (1-x)(tan(πx/2)) = 2 / π
et voilà, Mademoiselle !
hope it' ll help !!
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Verified answer
well, hello from France !
"and it goes like this..."
f(x) = (1-x)(tan(πx/2))
we will use the result :
lim (a ----> 0) tan(a)/a = 1
so
let be : e = 1 - x, we then have :
(1-x)(tan(πx/2)) = e tan( (π/2)(1 - e) )
= e tan( π/2 - πe/2)
= e / tan(πe/2)
= (2/π) (πe/2) / tan(πe/2) ------> 2 / π
so for a = πe/2 ----> 0 when e -----> 0 (when x > 1)
lim ( x -----> 1 of ) (1-x)(tan(πx/2)) = 2 / π
et voilà, Mademoiselle !
hope it' ll help !!