It takes 5.07 J of work to stretch a Hooke’s-law?
It takes 5.07 J of work to stretch a Hooke’s-law
spring 4.12 cm from its unstressed length.
How much the extra work is required to
stretch it an additional 8 cm?
Answer in units of J
Update:wait what is k?
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Verified answer
extra work required W = (1/2)K ( x2^2 - x1^2 )- U1, where U1 = 5.07 J, x1 = 4.12 cm and x2 = 8 cm
substitute the value and solve for work done W.
438746J??? I know it looks weird....but I had to try/./