Integration Problem: ∫x+12/(2-4x)^(1/2)?
I know it's done using the u-substitution way but i cannot seem to find the right procedure, can anybody show me how to solve this and explain, please?
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I know it's done using the u-substitution way but i cannot seem to find the right procedure, can anybody show me how to solve this and explain, please?
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u = 2 - 4x ⇒ x = (2 - u) / 4 ⇒ x + 12 = (50 - u) / 4
du = -4 dx
(-1/16) ∫ (50 - u) du / √u
Distribute and then power rule.