If 72.4 kJ of heat is supplied to a 762 g block of metal, the temperature of the metal increases by 9.4°C. Cal?
I really wanna know the answer but if you could unclude how to do it id be grateful
Update:Calculate the specific heat capacity of the metal in J/g·°C.
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q = g X C X delta T
energy = mass X specific heat X change in temperature
change it to find specific heat
energy / (mass X change temp.) = specific heat
72.4 kj = 72400 joules
72400/ (762g X 9.4) = 10.1 joules/gram degreeC