please show me the work, i need to understand this problem
1)find the zeros of -3x^2 e^-2x +3xe^-2x
1) =(16x^3y^8z^4)^1/3=2x y^2 z(2 y^2/3 z^1/3)
============================================
3x e^-2x(1-x)=0
x=0
x=+ infinity
x=1
God bless you.
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Verified answer
1) =(16x^3y^8z^4)^1/3=2x y^2 z(2 y^2/3 z^1/3)
============================================
3x e^-2x(1-x)=0
x=0
x=+ infinity
x=1
God bless you.