I suppose you can draw the line h(x) = -2x? Well do that, but only on the left side of the Y axis. When this line passes origo, it will be mirrored upwards on the X axis, as if it was the line h(x) = 2x.
Consequently, the domain will be all real numbers, the range will be all real numbers >= 0.
This will ensure that h(x) is always positive irrespective of value of x.
The graph will look like as below. (its plotted only for x value from -10 to +10 but can be expanded)
As the equation would give you a value of h(x) for any value of x, the range is -infinity to +infinity. But because value of h(x) is always positive, range of function is 0 to + infinity.
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This will look like a big V
I suppose you can draw the line h(x) = -2x? Well do that, but only on the left side of the Y axis. When this line passes origo, it will be mirrored upwards on the X axis, as if it was the line h(x) = 2x.
Consequently, the domain will be all real numbers, the range will be all real numbers >= 0.
If I split this equation,
h(x) = 2x, for x >= 0, and
h(x) = -2x, for x < 0.
This will ensure that h(x) is always positive irrespective of value of x.
The graph will look like as below. (its plotted only for x value from -10 to +10 but can be expanded)
As the equation would give you a value of h(x) for any value of x, the range is -infinity to +infinity. But because value of h(x) is always positive, range of function is 0 to + infinity.
Hope this helps.