How about a limit comparison with Σ (2/3)^n from n = 1 to infinity ???
If the limit of the ratio of your a-sub-n over my b-sub-n as n goes to infinity is finite and positive, then your series is convergent since my series is a convergent geometric series.
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How about a limit comparison with Σ (2/3)^n from n = 1 to infinity ???
If the limit of the ratio of your a-sub-n over my b-sub-n as n goes to infinity is finite and positive, then your series is convergent since my series is a convergent geometric series.