n=236
p= 1/365 (probability of person being born on July 4)
Mean = np = (236)(1/365) = 0.64657
Standard deviation = sqrt( np(1-p) ) = sqrt( (236)(1/365) (1-1/365) ) =0.803
Assuming the birthdays are independent and equally probable, you have a binomial distribution.
n = 236
p = 1/365
μ = pn ≈ 0.647
σ² = np(1 - p) ≈ 0.645
σ ≈ 0.803
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
n=236
p= 1/365 (probability of person being born on July 4)
Mean = np = (236)(1/365) = 0.64657
Standard deviation = sqrt( np(1-p) ) = sqrt( (236)(1/365) (1-1/365) ) =0.803
Assuming the birthdays are independent and equally probable, you have a binomial distribution.
n = 236
p = 1/365
μ = pn ≈ 0.647
σ² = np(1 - p) ≈ 0.645
σ ≈ 0.803