Find the area of rhombus RHOM if RO = 13.8 inches and m∠RHO = 68.
Round to the nearest hundredth place
See drawing below
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For a rhombus the area is half the product of the diagonals
Area = (Diagonal 1 * Diagonal 2) / 2
We are given diagonal RO as 13.8"
Draw in diagonal MH
this creates right triangle CHO
CH = (13.8/2) * tan 56
CH = 10.229670682737908
Since CH is half of diagonal MH
Area = 13.8 * 10.229670682737908
Area = 141.1694554218
Area ≈ 141.17 in² <–––––––
The area formula if you have had it is A = a b sin C where a and b are two sides and C is the included angle.
Have you had the law of cosines? If so call the sides x. You get 13.8² = x² + x² - 2xx cos 68
2x² - 2x² cos 68 - 13.8² = 0
x = 12.339212... so plug that in for x • x • sin 68
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Verified answer
See drawing below
----------------------
For a rhombus the area is half the product of the diagonals
Area = (Diagonal 1 * Diagonal 2) / 2
We are given diagonal RO as 13.8"
Draw in diagonal MH
this creates right triangle CHO
CH = (13.8/2) * tan 56
CH = 10.229670682737908
Since CH is half of diagonal MH
Area = 13.8 * 10.229670682737908
Area = 141.1694554218
Area ≈ 141.17 in² <–––––––
The area formula if you have had it is A = a b sin C where a and b are two sides and C is the included angle.
Have you had the law of cosines? If so call the sides x. You get 13.8² = x² + x² - 2xx cos 68
2x² - 2x² cos 68 - 13.8² = 0
x = 12.339212... so plug that in for x • x • sin 68