tan(3θ-4°)=1/cot(5θ-8°)
answer: Ѳ=2⁰
tan (3θ-4°)=1/cot (5θ-8°)
⇒ tan (3θ-4°)=tan (5θ-8°) [Note that tan θ = 1/cot θ]
⇒ 3θ-4° = 5θ-8°
⇒ 2θ = 4°
⇒ θ = 2°
you know that the ti 89 has an "solver" you plug in the equation and it finds the missing variable for you....
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tan (3θ-4°)=1/cot (5θ-8°)
⇒ tan (3θ-4°)=tan (5θ-8°) [Note that tan θ = 1/cot θ]
⇒ 3θ-4° = 5θ-8°
⇒ 2θ = 4°
⇒ θ = 2°
you know that the ti 89 has an "solver" you plug in the equation and it finds the missing variable for you....