Calculating the limit of f(x) at x=1, x=+∞
f (x) = (sqrt(x) + sqrt(x-1) / (sqrt(x) - 1)
Thanks for your help
for x = inf
we have lim f = lim (sqrt(x) + sqrt(x-1) / (sqrt(x) - 1) = lim (only the highest powers of x are needed)
= lim (sqrt(x) + sqrt(x) / (sqrt(x)) = 2
for x = 1
note that (sqrt(x) + sqrt(x-1) for x = 1 gives 1
In the divisor, we have sqrt(1) - 1 = 0
so the limit is + infinity if we approach x = 1 from the right
and the limit is - inf if we approach x = 1 from the left
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Verified answer
for x = inf
we have lim f = lim (sqrt(x) + sqrt(x-1) / (sqrt(x) - 1) = lim (only the highest powers of x are needed)
= lim (sqrt(x) + sqrt(x) / (sqrt(x)) = 2
for x = 1
note that (sqrt(x) + sqrt(x-1) for x = 1 gives 1
In the divisor, we have sqrt(1) - 1 = 0
so the limit is + infinity if we approach x = 1 from the right
and the limit is - inf if we approach x = 1 from the left