z=i3-i2+i17-i35/i16-i13+i30 , então z vale?
Ola Jessica
potencias de i
i^(4k) = 1
i^(4k+1) = i
i^(4k+2) = -1
i^(4k+3) = -i
z = (i^3 - i^2 + i^17 - i^35)/(i^16 - i^13 + i^30)
z = (-i + 1 + i + i)/(1 - i - 1)
z = (1 - i)/-i = (-i + 1)/-1 = -1 + i
pronto
z = -0,515
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Verified answer
Ola Jessica
potencias de i
i^(4k) = 1
i^(4k+1) = i
i^(4k+2) = -1
i^(4k+3) = -i
z = (i^3 - i^2 + i^17 - i^35)/(i^16 - i^13 + i^30)
z = (-i + 1 + i + i)/(1 - i - 1)
z = (1 - i)/-i = (-i + 1)/-1 = -1 + i
pronto
z = -0,515