A tire 0.44 m in radius rotates at a constant rate of 91.7 rev/min. Find the speed (relative to the tire’s axl?
A tire 0.44 m in radius rotates at a constant rate of 91.7 rev/min.
Find the speed (relative to the tire’s axle) of a small stone lodged in the tread on the outer edge of the tire.
Answer in units of m/s
Find the acceleration of the stone.
Answer in units of m/s2
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Verified answer
Perimeter of tyre = pi(0.88 x 2) = 5.52992m.
(91.7/60s) x 5.52992 = speed of 8.45m/sec. relative to axle. (8.451561067)
Acceleration = (v^2/r) = 162.34m/sec^2.
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