A marble is projected up along a 24 ° incline track at an initial speed of 2.7m/s and then coasts without friction.
(a) How long does it take for the marble to come to rest momentarily? s
(b) How far did the marble travel before it comes to its momentary rest point? m
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Verified answer
The (-) acceleration of the marble .. a = net force / mass
As friction is zero, the net force = weight component (- mg sin24) down the incline
a = - (mg sin24) / m
a = -g sin24 .. 9.80 x sin24 .. .. a = - 3.99 m/s²
1) v = u + at .. (final vel v = 0, a = - 3.99m/s²)
t = -u / a .. .. t = -2.70 / -3.99 .. .. ►t = 0.68s
2) v² = u² + 2ad .. (v = 0, a = -3.99m/s²)
d =-u² / 2a .. .. -2.70² / (2 x -3.99) .. .. ►d = 0.91 m