ƒ(x)=tan4x, what is ƒ'(x)=?
I tried this particular question a couple of times. I ended up with
ƒ'(x)=sec squared(4x)*4
How is this wrong? I'm using the chain rule.
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I tried this particular question a couple of times. I ended up with
ƒ'(x)=sec squared(4x)*4
How is this wrong? I'm using the chain rule.
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Verified answer
f(x) can be written as sin4x/cos4x
now we would apply division rule.
[4cos4x*cos4x - sin4x(-4sin4x)]/cos^24x
[4cos^2 4x+ 4 sin^2 4x]/cos^2 4x
4[cos^2 4x+ sin^2 4x]/cos^2 4x
4( 1+ tan ^2 4x) = 4 sec^2 4x
your answer is right. this is how the result is to be arrived at.