Find the are of the region (Calculus 2):
ƒ(x)=sin x g(x)=cos2x -π/2≤x≤π/6
you can do the integration : for x in [ - π / 2 , π / 6 ] integrate [ | cos 2x - sin x | dx ]
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you can do the integration : for x in [ - π / 2 , π / 6 ] integrate [ | cos 2x - sin x | dx ]