approach:a million utilizing integration with assistance from parts formulation. right here we've x^2 so we could use above formulation 2 circumstances. approach:2 [simplest approach] we use the formulation INT[e^x{f(x)+f'(x)}] dx = e^xf(x)+c.............(I) to apply this we construct f(x), for that (x^2)'=2x so subtract 2x from x^2 as we do not have any time period of x initially. now(-2x)'= -2 so upload 2 in x^2-2x as we do not have any consistent time period then INT{x^2e^x} dx =INT{e^x[(x^2-2x+2)+(2x-2)]} dx e^x{x^2-2x+2}+c [with assistance from (I)] so B= -2 consequently the answer is a. be conscious:FOR prepare OF approach 2 ,you come across INT[e^x{4x^3-7x+11} dx,and verify your very last answer with assistance from differntitating.
Answers & Comments
Verified answer
the answer is d because the integral is
(ê^(2x) ·(2·x^2 - 2·x + 1)) / 4
therefore your B part of the equation is -2x/4
so -1/2
approach:a million utilizing integration with assistance from parts formulation. right here we've x^2 so we could use above formulation 2 circumstances. approach:2 [simplest approach] we use the formulation INT[e^x{f(x)+f'(x)}] dx = e^xf(x)+c.............(I) to apply this we construct f(x), for that (x^2)'=2x so subtract 2x from x^2 as we do not have any time period of x initially. now(-2x)'= -2 so upload 2 in x^2-2x as we do not have any consistent time period then INT{x^2e^x} dx =INT{e^x[(x^2-2x+2)+(2x-2)]} dx e^x{x^2-2x+2}+c [with assistance from (I)] so B= -2 consequently the answer is a. be conscious:FOR prepare OF approach 2 ,you come across INT[e^x{4x^3-7x+11} dx,and verify your very last answer with assistance from differntitating.