cos 45° = 12/c
c = 12/cos 45°
c = 12 √2_________option C
cos45 = 12/c
√2/2 = 12/c
√2c = 24
c = 24/√2 = 24√2/2 = 12√2
tan(45) = a/12
1 = a/12
a = 12
hypotenuse = sqrt(12^2+12^2)
= sqrt(144+144) = sqrt(288) = sqrt(2*144) = √2sqrt(144) = 12√2
=12√2
degree 45-45-90 edge 1, 1 ,√2
so length of the hypotenuse is 12√2
C. 12√2
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Verified answer
cos 45° = 12/c
c = 12/cos 45°
c = 12 √2_________option C
cos45 = 12/c
√2/2 = 12/c
√2c = 24
c = 24/√2 = 24√2/2 = 12√2
tan(45) = a/12
1 = a/12
a = 12
hypotenuse = sqrt(12^2+12^2)
= sqrt(144+144) = sqrt(288) = sqrt(2*144) = √2sqrt(144) = 12√2
=12√2
degree 45-45-90 edge 1, 1 ,√2
so length of the hypotenuse is 12√2
C. 12√2