Use 1.00 g/mL as the density of water.
It's a weighted average:
((330.0 mL x 25.00 °C) + (100.0 mL x 95.00 °C)) / (330.0 mL + 100.0 mL) = 41.28 °C
The volume ratio is 10:33
Over the temperature range (95 - 25 = 70) we need to apply this ratio.
Hence
10 + 33 = 43
70 /43 = 1.6279 ( 1 ratio)
Hence 10 ratios is 16.279
& 33 ratios is 53.720
Hence water temperature rises by 25 + 16.28 = 41.28 degrees
Or fall by 95 - 53.72 = 41.27 degrees.
Hence final temperature of water is 41.27 degrees C
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Answers & Comments
It's a weighted average:
((330.0 mL x 25.00 °C) + (100.0 mL x 95.00 °C)) / (330.0 mL + 100.0 mL) = 41.28 °C
The volume ratio is 10:33
Over the temperature range (95 - 25 = 70) we need to apply this ratio.
Hence
10 + 33 = 43
70 /43 = 1.6279 ( 1 ratio)
Hence 10 ratios is 16.279
& 33 ratios is 53.720
Hence water temperature rises by 25 + 16.28 = 41.28 degrees
Or fall by 95 - 53.72 = 41.27 degrees.
Hence final temperature of water is 41.27 degrees C