Verified answer

1.1 × 10–4 mol(1000ml/0.29 mol)=0.38 ml

.38 mL (answer)

0.29 M NaBr x 0.00038 L = 1.1 x 10^-4 moles

the astonishing answer is NaBr. Please comprehend that bromine has the valency of two whilst bromide is Br-. Bromine is an oxidizer, and it will oxidize iodide ions (between others) to iodine, being itself decreased to bromide: Br2 + 2 I? ? 2 Br? + I2 So consequently Iodide is used to transform Br2 into Br-. Such you have got yet another reaction to type NaBr.