-square root of a negative number is i multiplied by the square root of the positive value the same size- so you should get i^2 multiplied by the square root of 49 multiplied by the square root of 12.
-i is the square root of -1, so i^2 is -1.
-Square root of 49 is basically 7 (as you should know).
-EDIT: Possibly factor out something in the square root of 12?
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Verified answer
√-49 √-12
=7i √(-4*3)
=7i * 2i√(3)
=14i^2 √(3)
=14(-1) √(3)
= - 14√(3) answer//
√-49 √-12 = √[(-49)*(-12)] = √[(49)*(12)] = 7√(12) = 14√3
if √-49 is taken as -7i and √-12 is taken as +(√12)*i
But if both of them are taken as +7i and+(√12)*i or -7i and -(√12)*i, then the answer will be = -14√3
If I remember my maths correctly:
-square root of a negative number is i multiplied by the square root of the positive value the same size- so you should get i^2 multiplied by the square root of 49 multiplied by the square root of 12.
-i is the square root of -1, so i^2 is -1.
-Square root of 49 is basically 7 (as you should know).
-EDIT: Possibly factor out something in the square root of 12?
That should be enough to help you.
√-49 √-12 =
√((-1)(49)) √((-1)(4)(3) =
(7i)(2i)√3 =
14i^2 √3 =
-14√3
-14√3
ten