It is a dowloadable INTEL ".hex" file, used to program microprocessors, load ROMs etc, displayed on a screen.
Typically, a compiler takes a source code (in a given language or assembler), compile it and issues that kind of file.
The first 8 bytes are the address where the line will be stored, the hex bytes following are the actual binaries to be written to the device, and the last dots to mu are the visual representations of each of the characters to be programmed, where "non displayable characters" are displayed as dots, the others as normal characters.
Typically a screen seen on a program to control a device programmer.
I don't know what the mu is and that other stuff (the mid-dots) on the end is thrown in there for. looks like garbage. the stuff preceding it is hexadecimal.
Answers & Comments
Verified answer
It is hexadecimal
from the looks of it 00D0E8E4 is an address and 01 00 20 00 ... are values starting from that address.
This raw data that is stored in memory or on drive - it can be a bit of programming code or just data.
You need to know the context.
It is a dowloadable INTEL ".hex" file, used to program microprocessors, load ROMs etc, displayed on a screen.
Typically, a compiler takes a source code (in a given language or assembler), compile it and issues that kind of file.
The first 8 bytes are the address where the line will be stored, the hex bytes following are the actual binaries to be written to the device, and the last dots to mu are the visual representations of each of the characters to be programmed, where "non displayable characters" are displayed as dots, the others as normal characters.
Typically a screen seen on a program to control a device programmer.
Hexadecimal
I don't know what the mu is and that other stuff (the mid-dots) on the end is thrown in there for. looks like garbage. the stuff preceding it is hexadecimal.