What is the volume of the solution that would result by diluting 60.00mL of 9.17×10−2M NaOH to a concentration of 1.60×10−2M ?
(M1V1)=(M2V2)
M = molarity
V = volume
M1 = 0.0160
V1 = ?
M2 = 0.0917
V2 = 60.00 mL
Plug in equation
(0.0160)(V1) = (0.0917)(60.00 mL)
(0.0160)(V1)=(5.502)
0.0160/5.502 = 0.00290 mL
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Verified answer
(M1V1)=(M2V2)
M = molarity
V = volume
M1 = 0.0160
V1 = ?
M2 = 0.0917
V2 = 60.00 mL
Plug in equation
(0.0160)(V1) = (0.0917)(60.00 mL)
(0.0160)(V1)=(5.502)
0.0160/5.502 = 0.00290 mL