Please show me the steps to solving this problem,
thank you
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(x³-x²+x-1)/(x²-1)
x²(x-1)+ x - 1 ← factored out x² to get the (x-1)'s
= ———————
(x²-1)
x²(x-1)+ (x-1)
(x²-1) ← notice the difference of squares
(x²+1)(x-1) ← factored out (x-1)
= ——————
(x+1)(x-1) ← factored the difference of squares
(x²+1)(x∕-∕1)
= —————— ← now, cancel the (x-1)'s
(x+1)(x∕-∕1)
(x²+1)
= ———— ← ANSWER
x+1
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x² - 1 = (x+1)(x-1).
Using synthetic division to divide 1x³ - 1x² + 1x - 1 by (x-1):
1__-1__1__-1__| 1
___1__0__1
1__ 0__1__0
shows that x³ - x² + x - 1 = (x-1)(x² + 1).
Therefore the expression reduces to (x²+1)/(x+1).
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Verified answer
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(x³-x²+x-1)/(x²-1)
x²(x-1)+ x - 1 ← factored out x² to get the (x-1)'s
= ———————
(x²-1)
x²(x-1)+ (x-1)
= ———————
(x²-1) ← notice the difference of squares
(x²+1)(x-1) ← factored out (x-1)
= ——————
(x+1)(x-1) ← factored the difference of squares
(x²+1)(x∕-∕1)
= —————— ← now, cancel the (x-1)'s
(x+1)(x∕-∕1)
(x²+1)
= ———— ← ANSWER
x+1
_________________________________
x² - 1 = (x+1)(x-1).
Using synthetic division to divide 1x³ - 1x² + 1x - 1 by (x-1):
1__-1__1__-1__| 1
___1__0__1
1__ 0__1__0
shows that x³ - x² + x - 1 = (x-1)(x² + 1).
Therefore the expression reduces to (x²+1)/(x+1).