Verified answer

Since this is a geometric sequence, we know that it is multiplying not adding the terms. So we know that the multiple is 3, since 1x3=3 and 3x3=9. So lets find the other 11 numbers in the sequence (just keep multiplying by 3. So the numbers are: 1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683, and 59049. So now we just add all the numbers up to get: 88,573

sum of a geometric series = a X ( 1- r^n)/(1 - r)

here a = 1

r = 3

n=11

sum = 1 X 1 - 3^11/(1-3) = 1- 3^11/-2 =1- 177147 = - 177146/-2 = 88573

S = 3^(0) + 3^1 + 3^2 + ... + 3^9 + 3^10

S * 3 = 3^1 + 3^2 + 3^2 + ... + 3^10 + 3^11

3S - S = 3^11 - 3^0

2S = 3^11 - 1

S = (3^11 - 1) / 2

S = 88573

sum=[r^n-first term]/r-1

where r=3/1=9/3... here r is ratio of two successive terms where bigger term is numerator lower term is denominator.

n=11 which is given by u

so substitute it in sum

sum=[3^11-1]/3-1

=88, 573 which is 4th choice

Ask your colleague Karen... fairly! I published her the outcomes. it is in basic terms a million.5 is an top sure (no longer a decrease one as I mistakenly advised her) She published exactely an identical stuff.

88,573