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?x = x2 - x1 = 4 - (-3) = 7 = width (b). ?y = y2 - y1 = 3 - (-2) = 5 = excellent (h). the area may be the hypotenuse. h = sqrt(b^2+h^2) replacing: h = sqrt(7^2+5^2) h = sqrt(40 9+25) h = sqrt(seventy 4) h = 8.6
sqrt((delta x)^2 + (delta y)^2)
where delta x = q(x) - p(x) and delta y = q(y) - p(y)
you do the math.
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You might want to ask this question also under the categories Homework Help or Mathematics.
?x = x2 - x1 = 4 - (-3) = 7 = width (b). ?y = y2 - y1 = 3 - (-2) = 5 = excellent (h). the area may be the hypotenuse. h = sqrt(b^2+h^2) replacing: h = sqrt(7^2+5^2) h = sqrt(40 9+25) h = sqrt(seventy 4) h = 8.6
sqrt((delta x)^2 + (delta y)^2)
where delta x = q(x) - p(x) and delta y = q(y) - p(y)
you do the math.