Verified answer

y = 2x^2 - 12x + 10 (Notice the ^ for exponents!)

y = 2(x^2 - 6x) + 10

y = -2(x^2 - 6x + 9) + 10 + 18

y = -2(x - 3)^2 + 28

The axis of symmetry is x = 3.

What is the axis of symmetry for the graph of y = 2x2 − 12x + 10?

Sol y = 2x2 − 12x + 10

y= 2(x^2 -6x) +10

y = 2(x^2-6x +9) +10 - 9

y = 2(x-3)^2 +1

Therefore axis of symmetry is x=3 ........................Ans

y = 2x^2 - 12x + 10

0 = 2x^2 - 12x + 10

0 = x^2 - 6x + 5

0 = (x - 5)(x - 1)

x intercepts are 5 and 1. Distance between the x intercepts is 4. Half of that would provide line of symmetry so 4/2 = 2. Now adding this to intercept of 1 gives us 1 + 2 = 3 so x = 3.