So far I have 18^5 + 20x^3. What do I do with the 6π?
6π is a constant and its derivative is zero, so you have the answer.
What you are asking is :-
f ( x ) = 3x^6 + 5x^4 - 6Ï , find f ` ( x )
f ` ( x ) = 18 x^5 + 20 x^3
NOTE
6Ï is a contant and derivative of a constant = 0
18x^5 + 20x^3
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6π is a constant and its derivative is zero, so you have the answer.
What you are asking is :-
f ( x ) = 3x^6 + 5x^4 - 6Ï , find f ` ( x )
f ` ( x ) = 18 x^5 + 20 x^3
NOTE
6Ï is a contant and derivative of a constant = 0
18x^5 + 20x^3