HELP PLEASE!! Due to a temperature difference ΔT, heat is conducted through a brass plate that is 0.039 m?
Due to a temperature difference ΔT, heat is conducted through a brass plate that is 0.039 m thick. The plate is then replaced by an iron plate that has the same temperature difference and cross-sectional area. How thick should the steel plate be so that the same amount of heat per second is conducted through it?
More Questions From This User See All
Answers & Comments
Use the equation Q=kA(changeintemp)/L ...solve for the Q of the Brass first then substitute the number you get into the same equation except the new K for iron is 79. The area however remains .039^2.
Then just solve for the L which is the solution to your question.
So what you will have is Kbrass= 110 A= (.039^2) (changeintemp)= 1 L=.039
Q=110x.001521x1/.039 ....answer is 4.29
4.29=79x.001521x1/L ..... L = .02800m which is the answer.
HAHAHAHHHAHHA