a million.) x^(2)-8x-20=0 in this concern 2*-10=-20 and a couple of-10=-8, so insert 2 because the right hand time period of one ingredient and -10 because the right-hand time period of the different ingredient. (x+2)(x-10)=0 Set each and each of the elements of the left-hand fringe of the equation equivalent to 0. x+2=0_x-10=0 on account that 2 does no longer contain the variable to remedy for, pass it to the right-hand fringe of the equation by employing subtracting 2 from each and each part. x=-2_x-10=0 Set each and each of the elements of the left-hand fringe of the equation equivalent to 0. x=-2_x-10=0 on account that -10 does no longer contain the variable to remedy for, pass it to the right-hand fringe of the equation by employing including 10 to each and each part. x=-2_x=10 the full answer is the set of the guy innovations. x=-2,10 2.) 8x^(2)=24x on account that 24x contains the variable to remedy for, pass it to the left-hand fringe of the equation by employing subtracting 24x from each and each part. 8x^(2)-24x=0 ingredient out the GCF of 8x from each and every time period interior the polynomial. 8x(x)+8x(-3)=0 ingredient out the GCF of 8x from 8x^(2)-24x. 8x(x-3)=0 Set the only time period ingredient on the left-hand fringe of the equation equivalent to 0. 8x=0 Divide each and every time period interior the equation by employing 8. (8x)/(8)=(0)/(8) Simplify the left-hand fringe of the equation by employing canceling the immediately ahead factors. x=(0)/(8) 0 divided by employing any huge variety or variable is 0. x=0 Set each and each of the elements of the left-hand fringe of the equation equivalent to 0. x-3=0 on account that -3 does no longer contain the variable to remedy for, pass it to the right-hand fringe of the equation by employing including 3 to each and each part. x=3 the full answer is the set of the guy innovations. x=0,3
Answers & Comments
Verified answer
answers are 2 and -10!
x2+8x-20=0
(need numbers that add to 8 and multiply to 20)
(x+10)(x-2)=0
a million.) x^(2)-8x-20=0 in this concern 2*-10=-20 and a couple of-10=-8, so insert 2 because the right hand time period of one ingredient and -10 because the right-hand time period of the different ingredient. (x+2)(x-10)=0 Set each and each of the elements of the left-hand fringe of the equation equivalent to 0. x+2=0_x-10=0 on account that 2 does no longer contain the variable to remedy for, pass it to the right-hand fringe of the equation by employing subtracting 2 from each and each part. x=-2_x-10=0 Set each and each of the elements of the left-hand fringe of the equation equivalent to 0. x=-2_x-10=0 on account that -10 does no longer contain the variable to remedy for, pass it to the right-hand fringe of the equation by employing including 10 to each and each part. x=-2_x=10 the full answer is the set of the guy innovations. x=-2,10 2.) 8x^(2)=24x on account that 24x contains the variable to remedy for, pass it to the left-hand fringe of the equation by employing subtracting 24x from each and each part. 8x^(2)-24x=0 ingredient out the GCF of 8x from each and every time period interior the polynomial. 8x(x)+8x(-3)=0 ingredient out the GCF of 8x from 8x^(2)-24x. 8x(x-3)=0 Set the only time period ingredient on the left-hand fringe of the equation equivalent to 0. 8x=0 Divide each and every time period interior the equation by employing 8. (8x)/(8)=(0)/(8) Simplify the left-hand fringe of the equation by employing canceling the immediately ahead factors. x=(0)/(8) 0 divided by employing any huge variety or variable is 0. x=0 Set each and each of the elements of the left-hand fringe of the equation equivalent to 0. x-3=0 on account that -3 does no longer contain the variable to remedy for, pass it to the right-hand fringe of the equation by employing including 3 to each and each part. x=3 the full answer is the set of the guy innovations. x=0,3
x^2 + 8x − 20 = 0
Ans: (x+10)(x-2)=0
x= -10
x= +2
Is that supposed to be 2x or x(squared) ?