What are the magnitude and direction of the equilibrant? first answer unit is N second answer unit is degrees
F1x=34cos210=-29.4 N
F1y=34sin210=-17 N
F2x=54cos315=38.2 N
F2y=54sin315=-38.2 N
then
Fx=-29.4+38.2=8.8 N
Fy=-17-38.2=-47.2 N
F=(Fx^2+Fy^2)^1/2=48 N
θ=arctan(Fy/Fx)=280.6 °
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Verified answer
F1x=34cos210=-29.4 N
F1y=34sin210=-17 N
F2x=54cos315=38.2 N
F2y=54sin315=-38.2 N
then
Fx=-29.4+38.2=8.8 N
Fy=-17-38.2=-47.2 N
F=(Fx^2+Fy^2)^1/2=48 N
θ=arctan(Fy/Fx)=280.6 °