If 5.27 mol of ethane (C2H6) undergo combustion 2C2H6 + 7O2 −→ 4CO2 + 6H2O , how much oxygen is required? Answer in units of mol.?
If 5.27 mol of ethane (C2H6) undergo combustion
according to the unbalanced equation
C2H6 + O2 −→ CO2 + H2O ,
how much oxygen is required?
Answer in units of mol.
dimensional analysis pls
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2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
(5.27 mol C2H6) x (7 mol O2 / 2 mol C2H6) = 18.4 mol O2