Using trigonometric identities, the derivative of f(x) = tan(x) + sin(x) cos(x) can be
simplified to the form f '(x) = tan^2(x) + A cos^2(x).
What is the value of A?
f '(x) = sec^2x + cosx cosx - sinx sinx
f '(x) = sec^2x + cos^2x sin^2x
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Answers & Comments
f '(x) = sec^2x + cosx cosx - sinx sinx
f '(x) = sec^2x + cos^2x sin^2x