Verified answer

OK first the formula! : deltaH=MCdeltaT where delta means a change in

So delta h being the enthalpy change

M being the mass

C being specific latent heat of water which it 4.2kj

and delta T being change in temp

so enthalpy change = mass of water x specific latent heat x change in temp

enthalpy change = 22 x 4.2 x 194 (194 being change in temp of 152--42 = 194)

yOU GET 17925.6