The position of an object as a function of time is r⃗ =(3.2t+ 1.5 t2)i^+(1.7t− 2.0 t2)j^m, where t is the time?
The position of an object as a function of time is r⃗ =(3.2t+ 1.5 t2)i^+(1.7t− 2.0 t2)j^m, where t is the time in seconds.
A) Find the object’s magnitude of the acceleration.
B) What is the direction of the acceleration?
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A) a(t) = d²r/dt² = 3m/s² i - 4m/s² j
mag a = √(3² + 4²) m/s² = 5 m/s²
Θ = arctan(-4/3) = -53º + 180º (to get into Q2) = 127º (ccw from +x axis)