Verified answer

9a²-30=3a <==subtract 3a both sides

9a² - 3a - 30 = 0

3(3a² - a - 10) = 0

3(3a + 5)(a - 2) = 0

a = -5/3, 2

9a² - 30 = 3a

3a² - 10 = a

3a² - a = 10

a² - 1/3a = 10/3

a² - 1/6a = 10/3 + (- 1/6)²

a² - 1/6a = 120/36 + 1/36

(a - 1/6)² = 121/36

a - 1/6 = 11/6

1st factor:

= a - 1/6 - 11/6

= a - 2

2nd factor:

= a - 1/6 + 11/6

= a + 5/3

= 3a + 5

Values of a:

a - 2 = 0, x = 2

3a + 5 = 0, 3a = - 5, a = - 5/3

Answer: x = 2, 5/3; Factors: 3(a - 2)(3a + 5)

9a²-30=3a

divide by 3 on both sides

3a²-10=a

3a²-a-10=0

3a²-6a+5a-10=0

3a(a-2)+5(a-2)=0

(3a+5)(a-2)=0

Therefore,

either (3a+5)=0 ==> a = -5/3

or (a-2)=0 ==> a = 2

if u have to factor it, then u subtract 3a so ur equation reads

9a^2-3a-30=0

After that Im pretty sure you factor if thats what your homwork is.

factor out a 3 so it is

3 (3a^2-3a-30)=0

Next find the trinomial

3 ((-5 + -3a)(2 + -1a)) = 0

Set the equations set to 0 ignoring the 3.

-5+ -3a=0

2+ -1a=0

solve for a

-5+ -3a=0

+5 +5

-3a=5

a= -.166666667

Next equation

2+ -1a=0

-2 -2

-1a=-2

a=1

So your answers are a= {-.167,2)