√3tanθ + 1 = 0
√3 tan(θ) + 1 = 0
(sqrt(3) sin(2 θ))/(cos(2 θ) + 1) + 1 = 0
θ ≈ 0.16667 (18.850 n - 3.1416), n element Z
√3 tan Θ = -1
tan Θ = -1 / √3 = -√3 / 3
Since tan 30 = √3 / 3, and tan is negative in Q2 and Q4, changing 30 becomes 150° and 330°
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√3 tan(θ) + 1 = 0
(sqrt(3) sin(2 θ))/(cos(2 θ) + 1) + 1 = 0
θ ≈ 0.16667 (18.850 n - 3.1416), n element Z
√3 tan Θ = -1
tan Θ = -1 / √3 = -√3 / 3
Since tan 30 = √3 / 3, and tan is negative in Q2 and Q4, changing 30 becomes 150° and 330°