How would you Solve M=πr^2 hd for r?
The denominator has to be rationlized also
M=pi(r^2)hd
collect the r variables
[in this case, just one]
M=r^2(pi)hd
divide through by (pi)hd
M/((pi)hd)=r^2
r=+/-sqrt(M/((pi)hd))
M = π*r^2*h*d
r^2 = M/(π*h*d)
r = sqrt[M/(π*h*d)]
r² = M / (πhd)
r = √M / √(πhd)
r = √ (Mπhd) / (πhd)
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Answers & Comments
M=pi(r^2)hd
collect the r variables
[in this case, just one]
M=r^2(pi)hd
divide through by (pi)hd
M/((pi)hd)=r^2
r=+/-sqrt(M/((pi)hd))
M = π*r^2*h*d
r^2 = M/(π*h*d)
r = sqrt[M/(π*h*d)]
r² = M / (πhd)
r = √M / √(πhd)
r = √ (Mπhd) / (πhd)