ok i dont know what completing the square is, but heres the solution using the zero-product property:
x^2-6x=7 subtract 7 from both sides and you get...
x^2-6x-7=0 factor the left side to get
(x+1)(x-7)=0 now treat these as two separate equations:
x+1=0 and x-7=0 when you solve both using inverse operations (-1 from both sides for the first, +7 on both sides for the second), you get -1 and 7 which gives you a final answer of........
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ok i dont know what completing the square is, but heres the solution using the zero-product property:
x^2-6x=7 subtract 7 from both sides and you get...
x^2-6x-7=0 factor the left side to get
(x+1)(x-7)=0 now treat these as two separate equations:
x+1=0 and x-7=0 when you solve both using inverse operations (-1 from both sides for the first, +7 on both sides for the second), you get -1 and 7 which gives you a final answer of........
:) :) :) (sorry had to add the smileys)
x=7,-1
x^2 - 6x + 9 = 7 + 9
(x - 3) ^2 = 16
x-3 = +4 or -4
x = 7 or - 1