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Use brackets to show what exactly is going under square root. If the whole expression 3x-2 is, then the answer is b:

sqrt(3x-2) = sqrt(3*34-2) = sqrt(102-2) = sqrt(100)

10^2=10*10=100, so 10 is one of the roots of 100.

properly.....x is 4 and y is a million. Sorry, yet i do no longer keep in mind algebra adequate to truly do it utilising the addition approach. What I did to remedy it however is that if 3x - 2 = 10, then 3x - 2 (+2) = 10 (+2), so 3x = 12 and x = 4. Then I substituted x for 4 in 3x + 2y = 14, to get 12 + 2y = 14. Subtract 12 from the two aspects to get 2y = 2, and y = a million. i'm uncertain if that's relatively what you have been searching for, yet a minimum of I gave you the respond, top?

34

The first thing you have to do is to square both sides to cancel the square root.

[sqrt(3x-2)]^2=10^2

3x-2=100

Then add 2 to both sides

3x-2+2=100+2

3x=102

Then divide by 3 on both sides

3x/3=102/3

x=34

b.{34}

squaring both sides

3x-2 = 100

or 3x = 100+2 = 102

or x = 102/3 = 34

So option b is the right answer

√(3x - 2) = 10

3x - 2 = 100

3x = 102

x = 102/3 = 34

√3x-2 = 10

√3x = 12

x = 12 / √3

x = 4√3

None of those answers are right.

That's not a question; it's a command. Besides you should be doing your own homework so you can get a good job when you graduate instead of having to live in your parents basement all your life. There is going to be a LOT of competition when you get out of school. Are you going to be at the top - or the bottom?

3x-2=100

3x=102

x=102/3

x=34

b

b