and now let y=3x^3+5+(x^2+3x^2/3)/√x. Find dy/dx
thanks :)
(x^2 + 3x^(2/3)) / √x =
(x^2 + 3x^(2/3)) / x^(1/2) =
[x^2 / x^(1/2)] + [3x^(2/3) / x^(1/2)] =
x^(2 - 1/2) + 3x^(2/3 - 1/2) =
x^(3/2) + 3x^(1/6)
x^p + 3x^q = x^(3/2) + 3x^(1/6)
==> p = 3/2, q = 1/6
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Verified answer
(x^2 + 3x^(2/3)) / √x =
(x^2 + 3x^(2/3)) / x^(1/2) =
[x^2 / x^(1/2)] + [3x^(2/3) / x^(1/2)] =
x^(2 - 1/2) + 3x^(2/3 - 1/2) =
x^(3/2) + 3x^(1/6)
x^p + 3x^q = x^(3/2) + 3x^(1/6)
==> p = 3/2, q = 1/6