x² + x + 1 = 0
Δ² = 1 - 4 = -3
Δ = √3i
x1 = (-1 + √3i)/2
x2 = (-1 - √3i)/2
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Verified answer
x² + x + 1 = 0
Δ² = 1 - 4 = -3
Δ = √3i
x1 = (-1 + √3i)/2
x2 = (-1 - √3i)/2