(MACK-SP) O valor de log 0,01 ³√0,1 é ;?
(MACK-SP) O valor de log 0,01 ³√0,1 é ;
a)-1/2 b)-1/6 c)1/6 d)1/2 e)0,5
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(MACK-SP) O valor de log 0,01 ³√0,1 é ;
a)-1/2 b)-1/6 c)1/6 d)1/2 e)0,5
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log[(0.01)*raiz-3(0.1)]
log(0.01) + log(0.1)/3
-2 + (-1)/3= -7/3
Ola Julio
log0.01(³√0.1) = log(0.1)/3log(0.01)
-log(10)/3*log(1/100) = -1/3*(-2) = 1/6 (C)
pronto