Verified answer

6y^2+6-37y^2=

-31y^2=-6

Y^2=6/31

Y= sqrt. of 6/31.

6(y²+1) -37y² = 0

so, 6y²+6 -37y² = 0 so, -31y² =-6 so, y² =6/31 so, y=sqrt(6/31) or y=-sqrt(6/31)

both are possible because it is a quadratic equation

see x² =4 means x=2 or x=-2

hope you understand

6(y^2 +1) -37y^2 = 0

6(y^2+1) =37y^2

6y^2 = 37y^2 -6

6y^2 - 37y^2 = -6

Y^2(6-37) = -6

Y = + or - *square root* 6/31

Yeah i know its pretty complecated like this.. Try to write it down then maybe youll get it! :D

6(y^2 + 1) - 37y^2 = 0

6y^2 + 6 - 37y^2 = 0

-31y^2 +6 = 0

y^2 = (6/31)

y = (6/31)^0.5; y = -(6/31)^0.5

6(y2+1)-37y2=0

6y2+6-37y2=0

-31y2=6

y2=6/-31