Physics: A car coasts (engine off) up a 30° grade. If the speed of the car is 25 m/s at the bottom of the...?
A car coasts (engine off) up a 30° grade. If the speed of the car is 25 m/s t the bottom of the grade, what is the distance traveled by the car before it comes to rest?
Hint) a) ignore friction. calculate the acceleration from newton's second law, then use kinematics to calculate the distance. b) in addition, compute the time it takes the car the come to rest.
answers:
a) d = 64m
b) t = 5.12 s
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Verified answer
v^2 = 2as
25^2 = 2 x 9.8sin 30 x s
625 /9.8 = s
s = 64 m
v = u + at
0 = 25 - 9.8sin 30xt
t = 5.102