P(x) = (a-1)x³ + bx + (c-3) Onde A' = (a-1), B' = b e C = (c-3)

Q(x) = x³ + (2-b)x + 5 Onde A" = 1, B" = (2-b) e C = 5

P(x) = Q(x)

Então

A' = A"

B' = B"

C' = C"

(a - 1) = 1

a = 1+1

a = 2

b = 2 - b

b + b = 2

2b = 2

b = 1

c - 3 = 5

c = 5 + 3

c = 8

a-1=1

a=1+1

a=2

2-b=b

2=b+b

2b=2

b=2/2

b=1

c-3=5

c=5+3

c=8

(a - 1) = 1

a = 2

b = 2 - b

2b = 2

b = 1

c - 3 = 5

c = 8

pronto